Workout # 1 (DUE: Monday, October 15, 2012)

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Workout # 1 (DUE: Monday, October 15, 2012)

Post  engr.c on Fri Oct 12, 2012 12:39 am

WO#1

Answer the following problems

2.1, 2.2, 2.3, 2.4, 2.5, 2.6, 2.7, 2.8, 2.9, 2.10, 2.11, 2.12, 2.13, 2.14 and 2.18

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**All images are from the book Design of Reinforced Concrete by Jack McCormac (Seventh Edition)

**Also take note on how to compute for the area of steel with designation #(number here). You may refer to ConMet notes or the area can be obtain by dividing the number by 8. And, the result gives you the area of the rebar in in^2.


Last edited by engr.c on Fri Oct 12, 2012 5:30 pm; edited 1 time in total

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  mjcarlos on Fri Oct 12, 2012 4:21 pm

andami naman sir >.<
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RE: WORKOUT # 1 (DUE: MONDAY, OCTOBER 15, 2012)

Post  sib on Fri Oct 12, 2012 4:56 pm

Sir, sa 2.8-2.11, 1.5in po ba yung concrete cover & wala po ba talagang stirrups (kung meron ano po yung diameter)???
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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  engr.c on Fri Oct 12, 2012 5:25 pm

di considered si stirrups sa prob. but since ang definition kay effective depth, d, ay distance from the centroid of the rebars to the extreme comp fiber, di na kailangan si concrete cover at stirrups since shown na si effective depth sa figure.

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  johnbhel on Fri Oct 12, 2012 5:31 pm

HIIHIHHIHIHI.... BOOM PRACTICE PRACTICE DIN!!!

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  engr.c on Fri Oct 12, 2012 6:37 pm

TAPOS NA KO! HOOOO.

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  KSawali on Sun Oct 14, 2012 5:06 am

engr.c wrote:TAPOS NA KO! HOOOO.

Pakopya HAHA! =))))

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  IraBalmoris on Sun Oct 14, 2012 10:04 am

sir bakit ganun, di ko mapalabas sagot sa 2.9 xD Diba As = 3in^2, since ( 6 / 8 )*4 = 3?

at tsaka ano gagawin pag may kasamang beam weight?

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  engr.c on Sun Oct 14, 2012 10:37 am

Mag-iiba po yung sagot dahil dun sa pag-compute nila ng As. but we stick sa pagcompute natin na #/8.

Yung beam weight ay given naman si weight ni concrete.

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  delwinaustria@ymail.com on Sun Oct 14, 2012 12:00 pm

Very Happy

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  IraBalmoris on Sun Oct 14, 2012 1:10 pm

engr.c wrote:Mag-iiba po yung sagot dahil dun sa pag-compute nila ng As. but we stick sa pagcompute natin na #/8.

Yung beam weight ay given naman si weight ni concrete.

ahh bale di na po 1450 ang sagot dun?

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

Post  KSawali on Sun Oct 14, 2012 8:33 pm

IraBalmoris wrote:sir bakit ganun, di ko mapalabas sagot sa 2.9 xD Diba As = 3in^2, since ( 6 / 8 )*4 = 3?

at tsaka ano gagawin pag may kasamang beam weight?

As = [ pi/4 * .75^2 ] * 4

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seatwork # 2 answers

Post  burgydoria on Wed Oct 17, 2012 5:17 pm

Sir! pwede niyo po i-post yung answers sa seatwork #2 yung ginamitan namen ng probabilty. Smile salamat po

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Re: Workout # 1 (DUE: Monday, October 15, 2012)

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